Guessing Game Java Prompt to Guess Again

11-05-2015

I take made a programme which prompts the user to guess an integer at random between one and 1000. Here is the code along with comments:

Code:

// standard library #include "stdafx.h" #include <stdio.h> #include <iostream> #include <math.h> #include <stdlib.h> #include <time.h>  unsigned int random(); // image role  // first program int main() {         srand(fourth dimension(NULL)); // randomize random number generator without seed     unsigned int guessNumber = 0; // guess input received from user     unsigned int randomNumber = random(); // random number generated by function     char ch = 'y'; // user input to continue or end programme          printf("I have a number between 1 and k.\nCan y'all guess my number?\nPlease type your first estimate.\northward\n");          do    { // do while loop for playing the game      while (randomNumber != guessNumber)    { // inner while loop for when the user input does not equal the random number         scanf("%u", &guessNumber); // // obtain user's guess      if (randomNumber > guessNumber)    { // if the random number is higher than the user's guess         printf("Besides low.  Try again.\n");     }     else    { // if the random number is lower than the user'southward guess         printf("Besides high.  Attempt again.\due north");     }     }     if (randomNumber = guessNumber)    { // if the random number is equal to the user's guess         printf("\nExcellent!  You guessed the number!\north");         printf("\nWould you like to play again?\n\n");         ch = getchar(); // read character input from stdin         scanf("%c", &ch); // obtain yep or no from user     }     }     while (ch == 'y');       organisation("intermission");     return 0; } // cease program  // function random unsigned int random() {     unsigned int theRandomNumber = 1 + (rand() % 1000); return theRandomNumber; }

The problem is that at the cease of the plan if the user selects Y to play again (I am aware that anything other than Y volition cease it), Information technology only tells them they guessed the number correctly again and asks if they want to play again. I have been researched how to articulate the input buffer with scanf() to no avail. I accept also researched fgets(), and fscanf(); fgets() seems to only deal with char and fscanf() actually requires a file to be used as an statement. I am too bold there is a much more than legitimate fashion to articulate the input buffer with ane of these other functions. Could someone please signal me in the right direction? Thanks!

11-05-2015

Are you trying to learn C or C++?

Your first comment is wrong, <stdafx.h> is not a standard header.

The <iostream> header is a C++ header and will not work with a C compiler, your not using this so I advise you remove this line.

Y'all need to acquire the difference between the comparison operator== and the assignment operator=.

Code:

                        if (randomNumber = guessNumber)

Expect at this snippet:

Lawmaking:

                        if (randomNumber = guessNumber)    { // if the random number is equal to the user's guess         printf("\nExcellent!  You guessed the number!\n");         printf("\nWould you similar to play over again?\n\due north");         ch = getchar(); // read character input from stdin // What character are you trying to read???         scanf("%c", &ch); // obtain yes or no from user     }

What are y'all trying to accomplish with the last 2 lines? You tin force scanf() to skip leading whitespace by putting a infinite earlier the specifier:

Code:

scanf(" %c", &ch); // Note the space.

The problem is that at the end of the program if the user selects Y to play again

Remember C is case sensitive 'y' is not the same as 'Y'.

Lastly your indentation could use some serious improvements, be consistent.

Jim

eleven-05-2015

Quote Originally Posted by jimblumberg View Post

What are yous trying to accomplish with the concluding ii lines? You can force scanf() to skip leading whitespace past putting a space before the specifier:

Lawmaking:

scanf(" %c", &ch); // Note the infinite.

Remember C is instance sensitive 'y' is not the same every bit 'Y'.

Lastly your indentation could use some serious improvements, be consequent.

Jim

I stock-still the scanf office; it now looks equally such:

Code:

if (randomNumber == guessNumber)    { // if the random number is equal to the user's gauge         printf("\nExcellent!  Y'all guessed the number!\north");         printf("\nWould y'all like to play again?\n\n");         scanf(" %c", &ch); // obtain aye or no from user

Also, I apologize for not being clear, still information technology is 'y' that I input not 'Y', I simply typed 'Y' in my mail service.

The winning number is still in the input buffer after the user enters 'y', so it immediately gives the user the message "You guessed the number! Would y'all like to play once again?" Rather than starting at the beginning. I suspect this is because the winning number is still in the input buffer, which is why I want to articulate it.

xi-05-2015

Did you fix the post-obit problem?

Quote Originally Posted by jimblumberg View Post

You need to learn the divergence betwixt the comparing operator== and the consignment operator=.

Code:

                            if (randomNumber = guessNumber)

What most the #include problems and indenation?

Jim

eleven-05-2015

Quote Originally Posted by jimblumberg View Post

Did you set up the post-obit problem?

What about the #include bug and indenation?

Jim

My code at present looks as such:

Lawmaking:

#include "stdafx.h"  // standard library #include <stdio.h> #include <math.h> #include <stdlib.h> #include <time.h>      unsigned int random(); // prototype function  // offset program int main() {         srand(time(NULL)); // randomize random number generator without seed      unsigned int guessNumber = 0; // guess input received from user     unsigned int randomNumber = random(); // random number generated by function     char ch = 'y'; // user input to keep or end programme          printf("I have a number between 1 and thousand.\nCan you guess my number?\nPlease type your first guess.\due north\north");          exercise    { // do while loop for playing the game          while (randomNumber != guessNumber)    { // inner while loop for when the user input does not equal the random number             scanf("%u", &guessNumber); // // obtain user's guess          if (randomNumber > guessNumber)    { // if the random number is higher than the user's guess             printf("Also low.  Try again.\north");         }         else    { // if the random number is lower than the user's guess             printf("Too high.  Try once again.\n");         }         }         if (randomNumber == guessNumber)    { // if the random number is equal to the user's estimate             printf("\nExcellent!  You guessed the number!\n");             printf("\nWould you like to play again?\n\n");             scanf(" %c", &ch); // obtain yes or no from user         }     }     while (ch == 'y');       system("pause");     render 0; } // end program  // role random unsigned int random() {     unsigned int theRandomNumber = ane + (rand() % 1000);  return theRandomNumber; }

eleven-05-2015

So does your program work properly now?

If not, draw the problem and ask specific questions.

Jim

11-05-2015

Quote Originally Posted past jimblumberg View Post

So does your program piece of work properly now?

If not, describe the problem and ask specific questions.

Jim

I have now made changes to this portion of the code:

Code:

char ch[ane]; // user input to continue or end program

and

Code:

if (randomNumber == guessNumber)    { // if the random number is equal to the user'southward gauge             printf("\nExcellent!  Y'all guessed the number!\north");             printf("\nWould you like to play over again?\n\northward");             scanf("%s%*c", &ch);             fgets(ch, 99, stdin);         }         }      }     while (ch == "y");

Nonetheless, at present when the plan runs and the user guesses the correct answer, it prints "Would yous like to play again?", I enter a y for yes, it brings me to the next line, I enter a y for yes again, and information technology ends the plan. Why doesn't fgets() store y into ch every bit it is supposed to, so the do-while loop works properly? Should I utilize fgetc() instead?

11-05-2015

Why are you fifty-fifty using fgets()? And why are you lot using the "%s" format specifier in scanf()?

All y'all should need is:

Code:

if (randomNumber == guessNumber)    { // if the random number is equal to the user'south guess             printf("\nExcellent!  You guessed the number!\n");             printf("\nWould you like to play once again?\n\n");             scanf(" %c", &ch); // Notice the space earlier the %!         }         }      }     while (ch == "y");

Jim

11-05-2015

Code:

do    {         guessNumber = 0;          randomNumber = random();         while (randomNumber != guessNumber)    { // inner while loop for when the user input does not equal the random number             scanf(" %u", &guessNumber); // // obtain user's approximate          if (randomNumber > guessNumber)    { // if the random number is higher than the user's guess             printf("Likewise low.  Try again.\north");         }         else if (randomNumber < guessNumber)    { // if the random number is lower than the user's guess             printf("Too high.  Try again.\n");         }         }         if (randomNumber == guessNumber)    { // if the random number is equal to the user'southward guess             printf("\nExcellent!  You guessed the number!\n");             printf("\nWould you like to play over again? ");             scanf(" %c", &ch);         }              }     while (ch == 'y');

I am thinking the logic in inside this do-while loop is what is giving me trouble. Now, when the user enters the winning number and is prompted to enter 'y' to play once again, I enter 'y' once and so it goes to a new line. I enter 'y' once more and it puts me into an infinite loop. It seems to be bypassing the scanf() that comes right afterward inner while loop condition, am I correct?

xi-05-2015

Beginning your indentation needs work, this'll make following the logic easier:

Lawmaking:

                        exercise     {         guessNumber = 0;         randomNumber = random();         while (randomNumber != guessNumber)      // inner while loop for when the user input does not equal the random number         {             scanf(" %u", &guessNumber); // // obtain user's judge              if (randomNumber > guessNumber)      // if the random number is higher than the user'due south estimate             {                 printf("Too low.  Try again.\n");             }             else if (randomNumber < guessNumber)      // if the random number is lower than the user'southward guess             {                 printf("Also loftier.  Attempt over again.\north");             }         }         // This if argument is not actually needed, the only way y'all're going to go here is if the ii variables are equal.         if (randomNumber == guessNumber)      // if the random number is equal to the user'south guess         {             printf("\nExcellent!  You guessed the number!\n");             printf("\nWould you like to play again? ");             scanf(" %c", &ch);         }      }while(ch == 'y');

Your problem is that afterwards you enter the 'y' and press enter the program is expecting you to enter some other estimate. Since the prompt is above the loop you won't get prompted.

And so move the prompt inside the loop and yous should be ready.

Jim

xi-05-2015

I take succeeded in getting the programme to work in-so-far equally I want it to. This is the code:

Code:

#include "stdafx.h"  // standard library #include <stdio.h> #include <math.h> #include <stdlib.h> #include <fourth dimension.h>      unsigned int random(); // prototype part  // kickoff program int principal() {         srand(time(Nil)); // randomize random number generator without seed      unsigned int guessNumber = 0; // guess input received from user     unsigned int randomNumber = random(); // random number generated past part     char ch = 'y'; // user input to continue or cease program      do    {         printf("\nI have a number betwixt 1 and 1000.\nCan you gauge my number?\nPlease type your kickoff gauge.\n\north");         guessNumber = 0;          while ((randomNumber != guessNumber))    // inner while loop for when the user input does non equal the random number         {              scanf("%u", &guessNumber); // // obtain user's guess              if (randomNumber > guessNumber)    // if the random number is higher than the user's gauge             {                  printf("As well depression.  Try again.\due north");             }                 else if (randomNumber < guessNumber)    // if the random number is lower than the user'due south guess                 {                  printf("Also high.  Endeavor again.\n");                 }                      }         if (randomNumber == guessNumber)    // if the random number is equal to the user'due south guess             {              printf("\nExcellent!  You guessed the number!\n");             printf("\nWould you like to play again (y or n)? ");             scanf(" %c", &ch);             }     }     while (ch == 'y');      arrangement("pause"); render 0; } // end program  // function random unsigned int random() {     unsigned int theRandomNumber = ane + (rand() % 1000);  return theRandomNumber; }

I know my indentation needed piece of work..shall this suffice?

xi-05-2015

Better but still a lilliputian off. Should look more than like:

Code:

//#include "stdafx.h"  // standard library #include <stdio.h> #include <math.h> #include <stdlib.h> #include <time.h>  unsigned int random(); // prototype function  // start plan int main() {     srand(fourth dimension(NULL)); // randomize random number generator without seed      unsigned int guessNumber = 0; // guess input received from user     unsigned int randomNumber = random(); // random number generated by function     char ch = 'y'; // user input to go on or terminate program      do     {         printf("\nI take a number between 1 and 1000.\nCan you guess my number?\nPlease type your get-go approximate.\n\n");         guessNumber = 0;          while ((randomNumber != guessNumber))    // inner while loop for when the user input does non equal the random number         {             scanf("%u", &guessNumber); // // obtain user's estimate              if (randomNumber > guessNumber)    // if the random number is higher than the user'due south judge             {                 printf("Likewise low.  Try again.\n");             }             else if (randomNumber < guessNumber)    // if the random number is lower than the user's guess             {                 printf("Too loftier.  Try again.\n");             }         }         printf("\nExcellent!  You guessed the number!\n");         printf("\nWould you like to play once more (y or n)? ");         scanf(" %c", &ch);     }while (ch == 'y');      system("intermission");     render 0; } // terminate program  // function random unsigned int random() {     unsigned int theRandomNumber = i + (rand() % m);      render theRandomNumber; }

Jim

McKnight Maske1955

Guessing Game Java Prompt to Guess Again

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